x=(x^2-9x+20)/4x

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Solution for x=(x^2-9x+20)/4x equation: 



x=(x^2-9x+20)/4x

We move all terms to the left:

x-((x^2-9x+20)/4x)=0



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



We multiply all the terms by the denominator


x*4x)-((x^2-9x+20)=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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